A man have a $1,100 made of 20s and 50s. he have a total of 37 bills. How lots 50s does he hold? equation.?
Answers:
1100=20x+50(37-x)
1100=20x+1850-50x
1100=-30x+1850
1100-1850=-30x+1850-1850
-750=-30x
-750/-30=-30x/-30
25=x
25 $20s and 12 $50s
Ask that man.
Then ask him to share it around. Sharing is civilized :)
A popular poke about engine have a great website for population to bring back give support to. There are some society that ask stupid question on this website and try to nouns smart. What is this call?
12 --50s... and 25--20s.
the agency i figure it out be to start out beside adjectives 20s. This amout is 37 x 20 =740.
the difference between 1100-740=360.
the difference between 50 and 20 is 30.
if you pilfer the 360 you still inevitability to capture and divide by 30 (50-20)=12.
That mechanism you call for to receive 12 of the bills 50s, and that leaves 25 bills that are 20s
12 x 50=600
25 x 20=500
600+500=1100
no. of 50s = x
no. of 20s = y
eqn I : x+y = 37
eqn II: 50x + 20y= 1100
accordingly x= 12 i construe...solve the equations and check.
Let x= number of 20s
x(20)+(37-x)50=1100
20x+1850-50x=1100
-30x=-750
x=25
25 twenties and 12 50s.
let f be the number of fifty dollar bills and t be the number of 20 dollar bills.
Then:
f+t =37 this is the equation for the total number of bills
50f + 20t = 1100 this is the equation for the money
solve by substitution:
t = 37 -f
50f + 20(37-f) = 1100
50f +740 -20f = 1100
30f = 360
f =12
t = 37-12=25