Summer math work?
a store bought a $1000 shipment of sweaters and offered them for mart after a $15 markup on respectively sweater. All but 10 sweaters wer sold, and the store made a $400 profit on the sweaters. How heaps sweaters did the store buy?
Answers:
This is a well-mannered math problem. The company bought X sweaters at a price Y and we know X*Y=1000 also stated as x=1000/Y
We also know X-10 sweaters (10 smaller amount than they bought) be sold for a lb15 markup.
So $15(x-10)-10Y=$400 represents the sweaters they bought and sold minus the cost of the ones they bought and didn't supply. Simplifying this final expression you go and get 15X-150-10Y=400 and when you give 150 to both sides and divide by 5 you bring 3X-2Y=110 Solving for X we go and get 3X=110+2Y
Now we can finally answer the cross-question because we know X=1000/Y and 3X=110+2Y. So if X=1000/Y after 3X=3000/Y
so 3000/Y=110+2Y multiplying both sides by Y give us 3000=110Y + 2Ysqared or simplified 1500=55Y+Ysquared
solving this equation for Y you bring 1500 = 55(20) + 20squared so Y = 20
Now that we know Y = 20 we can jump backbone to the resourceful equation stating X*Y=1000 and if Y is 20 afterwards X=50
So the store bought 50 sweaters.
We can check the answer by taking 50 sweaters and selling 40 of them for a $15 profit making $600 and next not selling 10 sweaters that cost $20 respectively -$200 for a total profit of $400.
Good Luck on your homework and the subsequent answer is yours to do!
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Answers:
This is a well-mannered math problem. The company bought X sweaters at a price Y and we know X*Y=1000 also stated as x=1000/Y
We also know X-10 sweaters (10 smaller amount than they bought) be sold for a lb15 markup.
So $15(x-10)-10Y=$400 represents the sweaters they bought and sold minus the cost of the ones they bought and didn't supply. Simplifying this final expression you go and get 15X-150-10Y=400 and when you give 150 to both sides and divide by 5 you bring 3X-2Y=110 Solving for X we go and get 3X=110+2Y
Now we can finally answer the cross-question because we know X=1000/Y and 3X=110+2Y. So if X=1000/Y after 3X=3000/Y
so 3000/Y=110+2Y multiplying both sides by Y give us 3000=110Y + 2Ysqared or simplified 1500=55Y+Ysquared
solving this equation for Y you bring 1500 = 55(20) + 20squared so Y = 20
Now that we know Y = 20 we can jump backbone to the resourceful equation stating X*Y=1000 and if Y is 20 afterwards X=50
So the store bought 50 sweaters.
We can check the answer by taking 50 sweaters and selling 40 of them for a $15 profit making $600 and next not selling 10 sweaters that cost $20 respectively -$200 for a total profit of $400.
Good Luck on your homework and the subsequent answer is yours to do!